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Why do we code S9(4) comp. Inspite of knowing comp-3 will occupy less space ?


Here s9(4)comp is small integer ,so two words equal to 1 byte so totally it will occupy 2 bytes(4 words).here in s9(4) comp-3 as one word is equal to 12 byte.4 words equal to 2 bytes and sign will occupy 12 byte so totally it will occupy 3 bytes.



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